Home Improvement

Power Factor Correction Calculator

Enter the real power and the present and target power factors to see the reactive power to remove.

Your numbers

A number above 0 and below 1, from a meter or the bill.

Your own goal, above the present value and up to 1.

Adds the current before and after. For three phase use the line to line voltage.

Result

Reactive power to remove

42.132 kvar

Moves the power factor from 0.8 to 0.95 for 100 kW of real power.

Reactive power to remove
42.132 kvar
Apparent power before
125 kVA
Apparent power after
105.26 kVA
Apparent power saved
15.79%
How this was calculated
  1. The reactive power is kvar = kW x tan(arccos(power factor)). Before: 75 kvar. After: 32.868 kvar.
  2. The capacitor bank supplies the difference: 42.132 kvar.
  3. Apparent power in kVA is kW divided by the power factor, and current is kVA x 1,000 divided by the voltage (and by the square root of 3 for three phase).
  • This is the arithmetic only. Real installations must consider harmonics, switching, protection and the rules that apply to your site, so have a qualified person design and install any capacitor bank.

Calculated using SumPanda.com · https://sumpanda.com/power-factor-correction-calculator/

Results are estimates for general information. Verify important figures before relying on them.

Next step

How to use the power factor correction calculator

  1. Enter the real power in kilowatts that the load draws.
  2. Enter the present power factor and the target power factor you want. The target must be higher.
  3. Choose single or three phase and, if you want currents, enter the line voltage.
  4. Read the kvar to remove, the apparent power and current before and after, and the share of apparent power saved.

Formula

Reactive power = kW x tan(arccos(power factor))

Capacitor kvar = kW x (tan(arccos(present pf)) - tan(arccos(target pf)))

Apparent power (kVA) = kW / power factor

Current = kVA x 1,000 / voltage (single phase) or kVA x 1,000 / (square root of 3 x voltage) (three phase)

Real power does the work. Reactive power moves back and forth with no net work, and it adds to the current. Capacitors supply reactive power locally, so the supply carries less.

100 kW from 0.80 to 0.95

A 100 kW load at 0.80 has tan(arccos 0.80) = 0.75, so 75 kvar of reactive power. At 0.95 the tangent is 0.32868, so 32.868 kvar. The capacitor bank must supply the difference, 42.132 kvar. The apparent power falls from 125 kVA to 105.26 kVA, a saving of 15.79 percent.

A 250 kW load at 480 V three phase going from 0.70 to 0.90 needs 133.97 kvar and the current falls from 429.58 A to 334.11 A. A 50 kW single phase load at 240 V going from 0.75 to 0.98 needs 33.943 kvar and the current falls from 277.78 A to 212.59 A.

What the numbers mean

A low power factor makes cables and transformers carry more current than the work needs. Some electricity bills charge for it. A higher power factor lowers the current for the same real power, as the before and after values show.

For the conversion between kilowatts and amps with a power factor, see the kW to amps calculator. The generator wattage calculator helps with start-up loads, and the RLC impedance calculator works with reactive parts.

What the page does not do

The page finds the arithmetic for a steady load. Real systems have changing loads, harmonics and resonance with the supply, and over-correcting can raise the voltage or cause problems. Capacitor banks need protection and switching suited to the site, so have a qualified person select and install any equipment.

Assumptions and limits

  • The load is steady and its real power does not change when the power factor is corrected.
  • Power factor is a number above 0 and up to 1. The target must exceed the present value.
  • Voltage is optional. For three phase it is the line to line voltage.
  • Harmonics, switching steps and equipment ratings are not modeled.

Formulas reviewed October 10, 2026. See the calculation methodology for how SumPanda rounds, tests and sources its formulas.

Frequently asked questions

How do I calculate kvar for power factor correction?

Multiply the real power in kW by the difference of tan(arccos(pf)) for the present and target power factors. For 100 kW from 0.80 to 0.95 that is 42.13 kvar.

What does improving the power factor save?

It reduces the apparent power and the current for the same real power. Going from 0.80 to 0.95 cuts the apparent power by about 15.8 percent.

Can the target power factor be 1?

Yes, up to 1. Then the reactive power is fully removed in theory, but real systems rarely aim for exactly 1.

Is a capacitor bank the only way?

It is the usual way to supply reactive power locally. This page calculates the size needed and does not recommend a design.